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我需要一塊鋁板,或者鋁合金板 45x30mm,以45兩邊為支點,中間F=5kg=50(N)負載
需要不會彎曲的程度,鋁板厚度至少要多少?或者其他鋁合金也可以,需考慮價格

Ans:

L=30(mm)=3*10^(-2)m

F=50(N)

E=彈性係數=70*10^9(Gpa)

I=轉動慣量

=b*t^3/12

=45*t^3*10^(-12)/12 m^4

=15t^3/4*10^12 (m^4)

delta<=1(mm)

=0.001(mm)

=1*10^(-3)

=F*L^4/48EI......材力公式

=50*81*10^(-8)/{48*70*10^9*15t^3/4*10^12}

=5*81*4*10^4/(48*7*15t^3*10^10)

=27/4*7*10^6*t^3

t^3=27/28*1000

t=0.098795(m)=9.88(cm)......ans

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